緊急求助關於電子技術基礎的壹道計算題，求解題的過程啊。。。

Ve=4-0.7=3.3V

Ic≈Ie=Ve/RE=3.3/2=1.65mA

Ib=Ib/β=1.65/50=0.033mA

Vce=12=Ic(RE+RC)=12-1.65x5=3.75V

2）rbe=300+26mV/Ib=300+788=1088Ω=1.088K

Av=-β(RC//RL)/rbe=-50x1.2K/1.088K=-55

Ri=RB1//RB2//rbe=0.935K

Ro=Rc=3K